和之前二分查找的思路有点像注意right nums.length - 1class Solution { public int findMin(int[] nums) { int left -1; int right nums.length - 1; while(left 1 right){ int mid left (right - left) / 2; if(nums[mid] nums[nums.length - 1]){ right mid; }else{ left mid; } } return nums[right]; } } 二刷hot100-153.寻找旋转排序数组中的最小值
和之前二分查找的思路有点像注意right nums.length - 1class Solution { public int findMin(int[] nums) { int left -1; int right nums.length - 1; while(left 1 right){ int mid left (right - left) / 2; if(nums[mid] nums[nums.length - 1]){ right mid; }else{ left mid; } } return nums[right]; } } RELATED READING
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